|
Interactive Linear Programming |
| Min cX | |
| Subject to: | ![]() |
and X 0 | |
| with c = | ![]() |
bi| So, we must: | |
| Consider a new (m+1)*1 column-vector X= | ![]() |
| So, A was equal to: | ![]() |
| and we add the new column, so that A becomes: |
![]() |
| So, vector C was equal to: | ![]() |
| and we add | cn+1=0 |
| So that C becomes : | ( c1 | c2 | ... | cn | 0 ) |
bi| So, we must: | |
| Consider a new (m+1)*1 column-vector X= | ![]() |
| So, A was equal to: | ![]() |
| and we add the new column, so that A becomes: |
![]() |
| So, vector C was equal to: | ![]() |
| and we add | cn+1=0 |
| So that C becomes : | ( c1 | c2 | ... | cn | 0 ) |
| The new variable (n+1)*1 column-vector is: | ![]() |
| So A, that was equal to | ![]() |
| and becomes: | ![]() |
| ai,jx'i+a'i,jx''i |
| =ai,j(x'i-x''i) |
| =ai,jxi |
| cix'i+c'ix''i |
| =ci(x'i-x''i) |
| = cixi |
| The new vector C is the following: | ![]() |
| Maximize c1x1 + c2x2 +.....+ cnxn (Objective function) |
| Minimize -c1x1 - c2x2 -.....- cnxn |