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Interactive Linear Programming |
Min cX | |
Subject to: | ![]() |
and X![]() | |
with c = | ![]() |
So, we must: | |
Consider a new (m+1)*1 column-vector X= | ![]() |
So, A was equal to: | ![]() |
and we add the new column, so that A becomes: |
![]() |
So, vector C was equal to: | ![]() |
and we add | cn+1=0 |
So that C becomes : | ( c1 | c2 | ... | cn | 0 ) |
So, we must: | |
Consider a new (m+1)*1 column-vector X= | ![]() |
So, A was equal to: | ![]() |
and we add the new column, so that A becomes: |
![]() |
So, vector C was equal to: | ![]() |
and we add | cn+1=0 |
So that C becomes : | ( c1 | c2 | ... | cn | 0 ) |
The new variable (n+1)*1 column-vector is: | ![]() |
So A, that was equal to | ![]() |
and becomes: | ![]() |
ai,jx'i+a'i,jx''i |
=ai,j(x'i-x''i) |
=ai,jxi |
cix'i+c'ix''i |
=ci(x'i-x''i) |
= cixi |
The new vector C is the following: | ![]() |
Maximize c1x1 + c2x2 +.....+ cnxn (Objective function) |
Minimize -c1x1 - c2x2 -.....- cnxn |